3^2x+1=68

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Solution for 3^2x+1=68 equation: 



3^2x+1=68

We move all terms to the left:

3^2x+1-(68)=0

We add all the numbers together, and all the variables

3^2x-67=0

We move all terms containing x to the left, all other terms to the right

3^2x=67

x=67/1

x=67

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